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If G be the centroid of AABC and the area of AGBD is 6 sq. cm, where D is the midpoint of side BC, then the area of AABC is
G is centroid of $$\triangle$$ABC and D is mid point of BC
Also, ar ($$\triangle$$GBD) = 6 sq. cm
=> Area of $$\triangle$$ABC = 6 $$\times$$ $$\triangle$$GBD
= 6*6 = 36 sq. cm
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