Question 121
The radius of a circle is 6 cm. An external point is at a distance of 10 cm from the centre. Then the length of the tangent drawn to the circle from the external point upto the point of contact is
Solution
Given : OA = 6 cm and OB = 10 cm
To find : AB = ?
Solution : From $$\triangle$$OAB
=> $$AB = \sqrt{(OB)^2 - (OA)^2}$$
= $$\sqrt{10^2 - 6^2} = \sqrt{64}$$
= 8 cm
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