Question 121
The least among the fractions $$\frac{15}{16}, \frac{19}{20}, \frac{24}{25}, \frac{34}{35}$$ is
Solution
Given numbers can be resolved like ( 1- $$\frac{1}{16}$$), (1- $$\frac{1}{20}$$), ( 1- $$\frac{1}{25}$$), (1 - $$\frac{1}{35}$$)
hence smallest among them will be the one having maximum substraction from 1.
so answer is $$\frac{15}{16}$$
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