Question 120
If p and q represent digits, what is the possible maximum value of q in the statement 5p9 + 327 + 2q8= 1114?
Solution
We can break the sum according to 500 + 10p +9 + 327 + 200 + 10q + 8 = 1114
or 1027 + 17 + 10(p+q) = 1114
or (p+q) = 7
so for q to be maximum p will be zero then q = 7
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