Successive discount of 10%, 20% and 25% on the price of an article will reduce the price by

Let marked price = Rs. $$100$$

After 1st discount of 10%, price = $$100-(\frac{10}{100}\times100)$$

= $$100-10=90$$

After 2nd discount of 20% (on changed price), selling price = $$90-(\frac{20}{100}\times90)$$

= $$90-18=Rs.$$ $$72$$

After 3rd discount of 25%, net selling price = $$72-(\frac{25}{100}\times72)$$

= $$72-18=Rs.$$ $$54$$

$$\therefore$$ Price is reduced by = $$\frac{(100-54)}{100}\times100=46\%$$

=> Ans - (C)