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Question 122
A is a point on the x-axis with abscissa - 8 and B is the pint on the y-axis with ordinate 15. The length of AB is
Solution
Now, OA = 8 units and OB = 15 units
=> $$(AB)^2=(OA)^2+(OB)^2$$
=> $$(AB)^2=(8)^2+(15)^2$$
=> $$(AB)^2=64+225=289$$
=> $$AB=\sqrt{289}=17$$ units
=> Ans - (C)
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