If in a triangle ABC, the angles at B and C are 1.5 and 2.5 times of the angle at A respectively, then angle at B is
Let $$\angle$$A = $$2x$$
=> $$\angle$$B = $$1.5 * 2x = 3x$$
=> $$\angle$$C = $$2.5 * 2x = 5x$$
Now, in $$\triangle$$ABC
=> $$\angle$$A + $$\angle$$B + $$\angle$$C = 180°
=> $$2x + 3x + 5x = 180$$°
=> $$x = 18$$°
$$\therefore$$ $$\angle$$B = 3*18 = 54°
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