Question 120
In ΔABC, D, E, F are midpoints of AB, BC, CA respectively and ∠B = 90°, AB = 6 cm, BC = 8 cm. Then area of A DEF (in sq. cm) is
Solution
Given : AB = 6 cm and BC = 8 cm
To find : area of $$\triangle$$DEF
Solution : Since D, E and F are mid points of AB, BC and AC
=> area of $$\triangle$$DEF = $$\frac{1}{4}$$ $$\triangle$$ABC
= $$\frac{1}{4} * \frac{1}{2} * 8 * 6 = 6$$ sq. cm
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