The ratio of the quantities on an acid and water in a mixture is 1 : 3. If 5 liters of acid is further added to the mixture, the new ratio becomes 1 : 2. The quantity of new mixture in litres is
Let' say previously mixture has $$x$$ acid and $$3x$$ water.
So after adding 5 liters of acid ratio will be $$(x+5)$$ : $$3x$$ = 1:2
After solving for $$x$$ , we will get its value as 10
So new values will be 15 and 30 , total will be 45
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