In xy plane, P and Q are two points having coordinates (2, 0) and (5, 4) respectively. Then the numerical value of the area of the circle with radius PQ, is
Radius of circle = Distance between PQ = $$\sqrt{(5-2)^{2} + (4-0)^{2}}$$ = 5
So, area of square = $$\pi r^{2}$$ = $$\pi 5^{2}$$
= 25π
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