Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 118
In xy plane, P and Q are two points having coordinates (2, 0) and (5, 4) respectively. Then the numerical value of the area of the circle with radius PQ, is
Solution
Radius of circle = Distance between PQ = $$\sqrt{(5-2)^{2} + (4-0)^{2}}$$ = 5
So, area of square = $$\pi r^{2}$$ = $$\pi 5^{2}$$
= 25π
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
