Question 117

If $$x=(0.08)^2$$, $$y=\frac{1}{(0.08)^2}$$ and $$z=(1-0.08)^2 - 1$$, then out of the following, the true relation is

Solution

Given that $$x=(0.08)^2$$, $$y=\frac{1}{(0.08)^2}$$ and $$z=(1-0.08)^2 - 1$$

$$x=(0.08)^2$$ = 0.0064

$$y=\frac{1}{(0.08)^2}$$ = 12.5 x 12.5 = 156.25

$$z=(1-0.08)^2 - 1$$ = a negative number

hence we can say that

z < x < y

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