If $$x^4 + \frac{1}{x^4} = 23$$, then the value of $$(x-\frac{1}{x})^2$$ will be
it is given that $$x^4 + \frac{1}{x^4} = 23$$
$$x^2 + \frac{1}{x^2}$$ = $$\surd(25)$$ = 5
we need to calculate $$(x-\frac{1}{x})^2$$ = $$x^2 + \frac{1}{x^2} - 2$$
= 5 - 2 = 3
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