Question 118

In a cyclic quadrilateral ABCD m∠A + m∠B + m∠C + m∠D =?

Solution

In a cyclic quadrilateral, the sum of opposite angles = 180°

=> $$\angle$$A + $$\angle$$C = 180°

and $$\angle$$B + $$\angle$$D = 180°

=> $$\angle$$A + $$\angle$$B + $$\angle$$C + $$\angle$$D = 180° + 180° = 360°

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