Question 117

Side AB of rectangle of ABCD is divided into four equal parts by points X, Y, Z respectively. The ratio of the areas of Triangle XYC and the rectangle ABCD is ?

Solution

ratio of their areas = $$\frac{\frac{1}{2}bh}{LB}$$
= $$\frac{\frac{1}{2}\times\frac{1}{4}AB\times BC}{AB\times BC}$$
= 1: 8


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App