Question 117

Side AB of rectangle of ABCD is divided into four equal parts by points X, Y, Z respectively. The ratio of the areas of Triangle XYC and the rectangle ABCD is ?

ratio of their areas = $$\frac{\frac{1}{2}bh}{LB}$$
= $$\frac{\frac{1}{2}\times\frac{1}{4}AB\times BC}{AB\times BC}$$
= 1: 8

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