Question 116

If I be the incentre of ΔABC and ∠B = 70° and ∠C = 50°, then the magnitude of ∠BIC is

Solution

In $$\triangle$$ ABC

=> $$\angle$$A + $$\angle$$B + $$\angle$$C = 180°

=> $$\angle$$A + 70° + 50° = 180°

=> $$\angle$$A = 60°

Now, using properties of incentre, => $$\angle$$BIC = 90° + $$\frac{\angle A}{2}$$

=> $$\angle$$BIC = 90° + $$\frac{60^{\circ}}{2}$$

=> $$\angle$$ = 120°

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