Solution
Expression : $$x^{2}+\frac{1}{x^2}=66$$
=> $$(x - \frac{1}{x})^2 + 2 = 66$$
=> $$(x - \frac{1}{x})^2 = 64$$
=> $$x - \frac{1}{x} = \pm 8$$
To find : $$\frac{x^2-1+2x}{x}$$
= $$x - \frac{1}{x} + 2$$
= $$(8 + 2)$$ and $$(-8 + 2)$$
= 10 and -6
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