Question 115
Three numbers are in the ratio 3 : 4 : 5. The sum of the largest and the smallest equals the sum of the second and 52. The smallest number is
Solution
as the three numbers are in ratio of 3:4:5
let the smallest number be 3y
greatest number be 5y and other middle number be 4y
it is given that 3y + 5y = 4y + 52
y = 13
hence smallest number = 3 x 13 = 39
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