The difference between the ages of two men is 10 years. 15 years ago, the elder one was twice as old as the younger one. The present age of the elder man is?
Solution
Let A and B be two men, and let A be older than B
15 years ago, A's age was twice that of B.
Let 15 years ago, B's age = x
$$\therefore$$ 15 years ago, A's age = 2x
Difference between ages = 2x - x = x = 10 (given)
Present age of A = 2x + 15 = 35 yrs
Hence, option A is the correct choice.
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