The tangents drawn at the points A and B of a circle centred at 0 meet at P. If ∠AOB = 120° then ∠APB : ∠APO is :
Since, O is the centre of the circle . OA=OB=radius .
So. PO will be angular bisector of APB.
Hence, ∠APB : ∠APO = 2:1
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