The perimeter of the base of a right circular cylinder is ‘a’ unit. If the volume of the cylinder is V cubic unit, then the height of the cylinder is
Perimeter of base = $$2 \pi r = a$$
=> $$r = \frac{a}{2 \pi}$$
Volume of cylinder = $$\pi r^2 h = V$$
=> $$\pi (\frac{a}{2 \pi})^2 h = V$$
=> $$a^2 h = 4 \pi V$$
=> $$h = \frac{4 \pi V}{a^2}$$
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