Question 108

A sphere of diameter 6 cm is dropped in a right circular cylindrical vessel partly filled with water. The diameter of the cylindrical vessel is 12 cm. If the sphere is just completely submerged in water, then the rise of water level in the cylindrical vessel is

Solution

Since, the sphere is completely submerged, then volume of both will be equal and rise of water level is equal to the height of cylinder.

=> $$\frac{4}{3} \pi R^3 = \pi r^2 h$$

=> $$\frac{4}{3} * 3^3 = 6^2 h$$

=> $$h = \frac{9 * 4}{36} = 1 cm$$

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