P can do a piece of work in 9 days. Q is 50% more efficient than P. The number of days it takes for Q to do the same piece of work is
P can do a piece of work in 9 days.
let efficiency of p is 100%
then efficiency of Q will be 150%
let Q can do the same piece of work in x days.
work is constant. soÂ
efficiency*no of days = constant
100*9 = 150*x
x = 6.
answer is option D.
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