Question 104

The average marks obtained by 22 candidates in an examination are 45. The average marks of the first 10 candidates are 55 and those of the last eleven are 40. The number of marks obtained by the eleventh candidate is

Solution

given that average marks obtained by 22 students =45

And average of first 10 students = 55

Average of last 11 students = 40

So using, average =$$\frac{sum}{numberofelements}$$

Sum of marks of all 22 students = 22x45= 990

Sum of students of first 10 students = 55x10= 550

Sum of last 11 students = 11x40 = 440

So marks obtained by 11th student = 990 -(550+440) = 0

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