Question 101

A person A having completed 60% of the work in 15 days, calls another person B and they together finish the remaining work in 5 days. Then how many days B alone would have taken to do the whole work?

Solution
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If A completes 60% of work in 15 days alone, then he can do entire work alone in 25 days. 
Now, it is given that A and B complete 40% of work together in 5 days.
Hence, A and B together can do entire work in 100/8 i.e. 12.5 days

Now, let B be able to do entire work alone in x days
Hence, going by the standard formula:
$$\frac{100}{8}=\frac{25x}{25+x}$$ ==> x = 25 days

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