$$\frac{9}{15}$$ of $$\frac{7}{3}$$ of a number is greater than $$\frac{7}{12}$$ of $$\frac{3}{5}$$ of the same number by 7. Find the number.
Let the number be $$x$$
According to ques,
=> $$(\frac{9}{15}\times\frac{7}{3}x)-(\frac{7}{12}\times\frac{3}{5}x)=7$$
=>Â $$(\frac{7x}{5})-(\frac{7x}{20})=7$$
=> $$\frac{x}{5}-\frac{x}{20}=1$$
=> $$\frac{4x-x}{20}=1$$
=> $$x=\frac{20}{3}=6.67$$
=> Ans - (B)
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