7/15 of 5/3 of a number is greater than 7/9 of 3/5 of the same number by 9. Find the quadruple of the number.
Let the number be $$45x$$
According to ques,
=> $$(\frac{7}{15}\times\frac{5}{3}\times45x)-(\frac{7}{9}\times\frac{3}{5}\times45x)=9$$
=> $$35x-21x=9$$
=> $$x=\frac{9}{14}$$
$$\therefore$$ Quadruple of the number =Â $$4\times45x$$
= $$180\times\frac{9}{14}\approx115.72$$
=> Ans - (A)
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