SNAP Profit and Loss Questions

This can be solved in an easier manner by using allegations concept.

$$p=\frac{\left(p1q1+p2q2\right)}{q1+q2}$$ where p1 ,p2 are profit percentages ,   q1,q2 are the number of articles , p is the overall profit percentage.

Here q1=3/5  ,  q2 =2/5 , p1=20 , p2=0

On solving you get p as 12

 P=50% and D=10%

The trader earns a revenue of Rs 54*20 after selling the items. = Rs 1080.

This is equivalent to a 50 percent profit.

Hence the cost price of all the items is Rs 1080*2/3 = Rs 720.

The revenue of Rs 1080 was earned after a discount of 10 percent.

If K is the marked price: K*(9/10) = K = Rs 1200.

Hence the profit percentage if no discount is provided :

$$\frac{\left(1200-720\right)}{720}\cdot100\ =\ 66.66\%$$

Let us assume that he uses x grams of weight instead of 1000gm.

Now, SP=CP*$$\frac{1000}{x}$$

$$\frac{SP}{CP}=\frac{1000}{X}$$

$$\frac{SP}{CP}-1=\frac{1000}{X}-1$$

$$\frac{5}{100}=\frac{1000}{X}-1$$

$$\frac{5}{100}+1=\frac{1000}{X}$$

$$\frac{105}{100}=\frac{1000}{X}$$

X=952.381

Total loss would be = Cost of food + Change that restaurant has  given suresh

= 162+37 + 338+63=600

$$\frac{\ 100000}{600000}\times\ 100\%\ =\ 16\ \frac{\ 2}{3}\%$$Let the Cost Price of the house be C.P

 $$\left(1+\ \frac{\ 5}{100}\right)C.P\ =\ 630000$$

$$\left(1.05\right)C.P\ =\ 630000$$

C.P = 600,000

If he sold house for 500,000; he would incur loss of 100,000

loss percent =  $$\frac{\ 100000}{600000}\times\ 100\%\ =\ 16\ \frac{\ 2}{3}\%$$

The profit will be shared based on amount and time the money was invested by person

For A : $$\left(16000\times\ 3\right)+\left(11000\times\ 9\right)$$ = 147,000

For B : $$\left(12000\times\ 3\right)+\left(17000\times\ 9\right)$$ = 189,000

For C : $$\left(21000\times\ 6\right)$$ = 126,000

Share of B will be $$\frac{189}{147+189+126}\times\ 26400\ =\ 10,800$$

Share of C will be $$\frac{126}{147+189+126}\times\ 26400\ =\ 7,200$$

Difference is 3,600

Let the cost price of the article be Rs.100x.

Marked price = Rs.130x

S.P. of the article = $$\ \frac{\ 130x\times\ 90}{100}$$ = Rs.117x

Actual percent profit = $$\ \frac{\ 117-100}{100}\times\ 100$$

=17%

D is the correct answer.

The cost price of the mixture per kg = $$\ \frac{\ 12\times\ 16+4\times\ 2}{12+4}$$

= Rs. 12.5

Selling price of the mixture per kg = Rs 16

Profit made on selling 1 kg of mixture = 16-12.5=Rs. 3.5

Profit made o selling 40 kg of mixture = 40*3.5=Rs. 140

A is the correct answer.

It is given that profit on 100 articles = SP of 75 articles

100(SP-CP) = 75*SP

4(SP-CP) = 3SP

SP = 4CP

Profit = $$\ \frac{\ SP-CP}{CP}\times\ 100$$

=$$\ \frac{\ 4CP-CP}{CP}\times\ 100$$

=300%

C is the correct answer.

Let the total sales in July 2009 be Rs. x
Then, sales in September 2009 = Rs. 2x/3
Sales in November 2009 :
= 105% of Rs.$$\ \frac{\ 2x}{3}$$
= Rs. $$\ \ \frac{\ 105}{100}\ \times\ \ \ \frac{\ 2x}{3}$$
= Rs. $$\ \frac{\ 7x}{10}$$
Now, the percentage change in sales :
$$\frac{\left(\frac{\ 7x}{10}-x\ \right)\ }{x}\times\ 100=\ \frac{\ -3x\ \ }{10x}\times\ 100\ =-30\%$$

A=P+SI
We get SI =2000
2000 = (6000*R*4)/100
we get R=25/3 %
Now
P =525
A =700
So SI = 175
175 = (525*25/3*T)/100
We get T = 4 years

Let the quantity of tea worth Rs.25 be x kg.
Now as per given
(25x+30×30)×110/100=30(30+x)
(275x+9900)=(9000+300x)
300x−275x=900=x=900/25
Therefore, x = 36 kg.

Assuming the total capital = 6 units and the total period = 12 months

Investment of A = 6*$$\ \frac{\ 1}{2}$$ = 3 units

Investment period of A = 12*$$\ \frac{\ 1}{3}$$ = 4 month

Investment of A = 6*$$\ \frac{\ 1}{3}$$ = 2 units

Investment period of A = 12*$$\ \frac{\ 1}{4}$$ = 3 months

Investment of A = 6*$$\ \frac{\ 1}{6}$$ = 1unit

Investment period of A = 12 months

Then the profit will be divided in the ratio (3*4):(2*3):(1*12) = 12:6:12 = 2:1:2

Let the C.P. per 1000 gm of the food grain for the merchant be x.

Let us now evaluate the options one by one.

Option A says the profit is straightaway 30%.

In option B, since the weight is reduced by 15%, he will be able to cheat by selling 850 grams instead of 1000 grams. 

So, his effective C.P. in this case will be 0.85x

Also, the S.P. is increased by 15% and so the S.P. will be 1.15x

Profit% in this case= $$\ \frac{\ SP-CP}{CP}\cdot100$$= $$\ \frac{\ 1.15x-0.85x}{0.85x}\cdot100$$= $$\ \frac{\ 0.3x}{0.85x}\cdot100$$=35.29%.

In option C, the shopkeeper cheats by selling 700 grams instead of 1000 grams. 

So, effective CP for the shopkeeper= 0.7x

The SP remains the same as original CP as nothing is mentioned about the change. So, SP=x

Profit% in this case= $$\ \frac{\ SP-CP}{CP}\cdot100$$= $$\ \frac{\ x-0.7x}{0.7x}\cdot100$$= $$\ \frac{\ 0.3x}{0.7x}\cdot100$$=42.8%

In Option D, if he mixes 30% impurities, for 1000 grams of food grain, he will be able to sell 1300 grams of food grains.

So, Effective CP remains the same=x

Effective SP= 1.3x

Profit% in this case= $$\ \frac{\ SP-CP}{CP}\cdot100$$= $$\ \frac{\ 1.3x-x}{x}\cdot100$$= $$\ \frac{\ 1.3x}{x}\cdot100$$=30%

We can see that the profit is maximum in the third case, and hence, Option C is correct.

The profit fraction will be divided based on the amount spent and the investment time

For A, the investment = (20,000*5) +(15,000*7) = 205,000

For B, the investment = (20,000*5) + ( 16,000*7) = 212,000

For C, the investment = (20,000*5) + ( 26,000*7) = 282,000

Profit share of B = $$\frac{212000}{205000+212000+282000}$$ = $$\frac{212}{699}$$

Share of B = $$69900\times\ \frac{212}{699}$$ = 21200