sbi-associate-po-2007

As per the rules value of C = 4
U= 5
S= 2*(19-4) = 30 {S position is 19th, but there will be 4 vowels in between so 19 - 4}
T= 32
O= 5
M= 2*(13-3) = 20
So the value of CUSTOM is, 4+30+32+20+10 = 96

Given sequence 3 7 6 5 8 3 2 4 5 5 4 8 7 9 1 5 3 4 8 7 5 9 8 7 6 4
5's for which the sum of following two digits is greater than the sum of preceding two digits are highlighted below
3 7 6 5 8 3 2 4 5 5 4 8 7 9 1 5 3 4 8 7 5 9 8 7 6 4, Thus there are 3 such 5's so option 3

$$P\times$$Q$$\div$$ R-T+S means P is the wife of Q and Q is father of R and R is the brother of T and T is the sister of S.

So, P is the mom and Q is the dad of R, T and S.

Hence (b) is the correct answer.

The required sequence is N O P Q R S T U V W X Y Z A B C D E F G H I J K L M
So, 17th letter from the right is W Now 9th letter to the right of W is F, so required answer is Option 1

T an executive is going to Chennai and is neither from Finance nor Marketing

W is a system specialist and is leaving for Delhi

U is an executive but is not going to one of the five places

Q is an executive from HRM but has come at the airport to see his friends

P is an executive but not from Marketing and is flying to one of the destinations but not to Bangalore or Calcutta

From the above information we can arrange the data as,

T - Chennai - Administration

W - Delhi - Systems

U - Nowhere - Marketing

Q - Nowhere - HRM

P - Lucknow - Finance

R - Bangalore/ Calcutta - No Specialization

S - Calcutta/ Bangalore - No Specialization

Hence either R or S is going to fly to Bangalore and it cannot be determined.

T an executive is going to Chennai and is neither from Finance nor Marketing

W is a system specialist and is leaving for Delhi

U is an executive but is not going to one of the five places

Q is an executive from HRM but has come at the airport to see his friends

P is an executive but not from Marketing and is flying to one of the destinations but not to Bangalore or Calcutta

From the above information we can arrange the data as,

T - Chennai - Administration

W - Delhi - Systems

U - Nowhere - Marketing

Q - Nowhere - HRM

P - Lucknow - Finance

R - Bangalore/ Calcutta - No Specialization

S - Calcutta/ Bangalore - No Specialization

Hence U specializes in Marketing.

T an executive is going to Chennai and is neither from Finance nor Marketing

W is a system specialist and is leaving for Delhi

U is an executive but is not going to one of the five places

Q is an executive from HRM but has come at the airport to see his friends

P is an executive but not from Marketing and is flying to one of the destinations but not to Bangalore or Calcutta

From the above information we can arrange the data as,

T - Chennai - Administration

W - Delhi - Systems

U - Nowhere - Marketing

Q - Nowhere - HRM

P - Lucknow - Finance

R - Bangalore/ Calcutta - No Specialization

S - Calcutta/ Bangalore - No Specialization

Hence R has no specialization.

T an executive is going to Chennai and is neither from Finance nor Marketing

W is a system specialist and is leaving for Delhi

U is an executive but is not going to one of the five places

Q is an executive from HRM but has come at the airport to see his friends

P is an executive but not from Marketing and is flying to one of the destinations but not to Bangalore or Calcutta

From the above information we can arrange the data as,

T - Chennai - Administration

W - Delhi - Systems

U - Nowhere - Marketing

Q - Nowhere - HRM

P - Lucknow - Finance

R - Bangalore/ Calcutta - No Specialization

S - Calcutta/ Bangalore - No Specialization

Hence the one who is going to fly to Chennai is T from Administration.

So, the question essentially asks to find out pairs of letters in the given word "NURSING" which have same number of letter between them as there are in english alphabet. We can start with the first letter initially and then try to check for subsequent letters. Lets take N, now NU have 6 letter between them in english alphabets, here they don't have any letter so this cannot be a possible pair. Lets move on to NR again NR have just 1 letter between them which is not the case in actual english alphabets. Proceeding in a similar manner we can find that words fulfilling the given requirement are

US, RS, IG Thus there are just 3 pairs of words meeting such requirement.

The pattern here followed is that the last word of the previous code becomes the first word for the next batch and the first and the second words shifted to the second and the third positions respectively. Again the seventh and the sixth words occupy the fourth and fifth positions respectively and then the third, the fourth and the fifth words of the previous code are written in the same order in the pass-code for the next batch.

To summarize, if we use numbers in place of the words, the arrangement will be :

Pass code for Batch I : 1 2 3 4 5 6 7 8

Pass code for Batch II : 8 1 2 7 6 3 4 5

Pass code for Batch III : 5 8 1 4 3 2 7 6

Pass code for Batch IV : 6 5 8 7 2 1 4 3

Pass code for Batch V : 3 6 5 4 1 8 7 2

Pass code for Batch VI : 2 3 6 7 8 5 4 1

=>Thus, we can write any required step from the given pass codes directly.

Pass code for Batch III : night succeed day and hard work to for = 5 8 1 4 3 2 7 6

Pass code for Batch VI : 2 3 6 7 8 5 4 1

=> work hard for to succeed night and day

Ans - (C)