RPF 5 Jan 2019

When a number is divided by 72 it leaves a remainder 8, let the number be = $$72 + 8 = 80$$

Now, when 80 is divided by 9, => $$80=9\times8+8$$

Thus, remainder = 8

=> Ans - (C)

Principal sum = Rs. 5400

Rate of interest = 8% and time period = 5 years

Simple interest = $$\frac{P\times R\times T}{100}$$

= $$\frac{5400\times8\times5}{100}=Rs.$$ $$2160$$

Thus, total amount after 5 years = $$Rs.$$ $$(5400+2160)=Rs.$$ $$7,560$$

$$\therefore$$ Remaining amount after half of the total amount is been invested in Share market = $$\frac{7560}{2}=Rs.$$ $$3780$$

=> Ans - (A)

Product of the 2 numbers = Product of L.C.M. and H.C.F.

= $$65\times8=520$$

=> Ans - (A)

The amount gets doubled in 3 years.

In case of compound interest, the amount will become $$2^n$$ times in $$3n$$ years

=> Final amount = $$128=(2)^7$$

Thus, after $$3\times7=21$$ years, amount will become 128 times.

=> Ans - (C)

Let cost price = Rs. 100

=> Marked price = $$100\times(\frac{136}{100})=Rs.$$ $$136$$

Thus, selling price after discount of 36% = $$136\times\frac{100-36}{100}=Rs.$$ $$87.04$$

$$\therefore$$ Loss % = $$\frac{100-87.04}{100}\times100=12.96\%$$

=> Ans - (C)

ABCD is the table and the glass piece is placed inside.

Side of glass = $$\sqrt{729}=27$$ cm

Width between glass and table = $$9$$ cm

=> Side of table = $$9+27+9=45$$ cm

=> Ans - (A)

Average weight of 101 Notebooks in a box = 10.1 kg

=> Total weight = $$101\times10.1=1020.1$$ kg

Let weight of new book = $$x$$ kg

=> New average = $$\frac{1020.1+x}{102}=10.2$$

=> $$1020.1+x=102\times10.2=1040.4$$

=> $$x=1040.4-1020.1=20.3$$ kg

=> Ans - (D)

% of non defective products = $$89\%\equiv5607$$

=> Number of defective products = $$11\%\equiv\frac{5607}{89}\times11$$

= $$63\times11=693$$

=> Ans - (C)

Let length of train = $$l$$ m and speed = $$s$$ m/s

Speed of train which takes 67 seconds to cross a bridge of length 266 m = $$s=\frac{266+l}{67}$$ -----------(i)

Also, $$s=\frac{l}{29}$$ --------------(ii)

Substituting value of $$s$$ from equation (ii) in (i), we get :

=> $$\frac{l}{29}=\frac{266+l}{67}$$

=> $$67l=(266\times29)+29l$$

=> $$67l-29l=38l=266\times29$$

=> $$l=\frac{266\times29}{38}=203$$

$$\therefore$$ Length of train = 203 m

=> Ans - (A)