RPF 5 Jan 2019

Average weight of first 4 rings = 37 grams

=> Weight of first 4 rings = $$37\times4=148$$ grams

Similarly, weight of remaining 6 rings = $$38\times6=228$$ grams

$$\therefore$$ Average weight of the total rings = $$\frac{148+228}{10}=37.6$$ grams

=> Ans - (B)

Let cost price of the article = Rs. $$x$$

Loss = Rs. $$(x-1234)$$

Profit = Rs. $$(2500-x)$$

According to ques, => $$\frac{P-L}{L}\times100=11$$

=> $$\frac{(2500-x)-(x-1234)}{(x-1234)}\times100=11$$

=> $$\frac{3734-2x}{x-1234}=\frac{11}{100}$$

=> $$11x-13574=373400-200x$$

=> $$11x+200x=373400+13574=386974$$

=> $$x=\frac{386974}{211}=1834$$

$$\therefore$$ Cost price = Rs. 1834

=> Ans - (D)

Total sales in the branches C1, C3 and C5 together for both the years (in thousands)

= (61 + 71) + (71 + 82) + (91 + 49) = 425

=> Ans - (A)

Selling price = Rs. 1386 and profit % = 12.5%

=> Cost price = $$\frac{1386}{(100+12.5)}\times100$$

= $$12.32\times100=Rs.$$ $$1232$$

$$\therefore$$ Amount which is equal to half of the cost price of the product = $$\frac{1232}{2}=Rs.$$ $$616$$

=> Ans - (C)

Number of trailing zeroes = $$\frac{142}{5}+\frac{142}{25}+\frac{142}{125}$$

= $$28+5+1=34$$     [Number will be round off to the lowest value]

=> Ans - (C)

Let ideal time taken = $$t$$ hours

Also, speed is inversely proportional to time.

=> $$\frac{36}{45}=\frac{t-\frac{5}{60}}{t+\frac{7}{60}}$$

=> $$4t+\frac{7}{15}=5t-\frac{5}{12}$$

=> $$5t-4t=\frac{7}{15}+\frac{5}{12}$$

=> $$t=\frac{28+25}{60}=\frac{53}{60}$$

$$\therefore$$ Distance = speed $$\times$$ time

= $$36\times(\frac{53}{60}+\frac{7}{60})$$

= $$36\times1=36$$ km

=> Ans - (C)

Radius of circle is directly proportional to perimeter, $$P=2\pi r$$

So, if radius is increased 9 times, hence the perimeter will become 9 times of its previous perimeter.

=> Ans - (A)

Expression : $$\frac{1}{12} \div \frac{1}{12} \div \frac{1}{12} \div \frac{1}{12} \div \frac{1}{12}$$

= $$[\frac{1}{12} \div \frac{1}{12}] \div [\frac{1}{12} \div \frac{1}{12} \div \frac{1}{12}]$$

= $$(1 \div \frac{1}{12}) \div \frac{1}{12} \div \frac{1}{12}$$

= $$(12\div\frac{1}{12})\div\frac{1}{12}$$

= $$12\times12\div\frac{1}{12}$$

= $$144\times12=1728$$

=> Ans - (A)

Let share of each kid be $$a,b,c,d$$ respectively.

Then according to ques, => $$a=2b=3c=4d=k$$

=> $$a=k$$ , $$b=\frac{k}{2}$$ , $$c=\frac{k}{3}$$ , $$d=\frac{k}{4}$$

Thus, total = $$a+b+c+d=500$$

=> $$k+\frac{k}{2}+\frac{k}{3}+\frac{k}{4}=500$$

=> $$k\times(\frac{12+6+4+3}{12})=500$$

=> $$k=500\times\frac{12}{25}=240$$

$$\therefore$$ Sum of gifts received by 1st kid and 2nd kid = $$a+b=k+\frac{k}{2}=3\frac{k}{2}$$

= $$3\times\frac{240}{2}=360$$

=> Ans - (A)

Expression : $$\sqrt{20.25} + \sqrt{75.69} + 8.7 = ?$$

= $$4.5+8.7+8.7=21.9$$

=> Ans - (B)