Let share of each kid be $$a,b,c,d$$ respectively.

Then according to ques, => $$a=2b=3c=4d=k$$

=> $$a=k$$ , $$b=\frac{k}{2}$$ , $$c=\frac{k}{3}$$ , $$d=\frac{k}{4}$$

Thus, total = $$a+b+c+d=500$$

=> $$k+\frac{k}{2}+\frac{k}{3}+\frac{k}{4}=500$$

=> $$k\times(\frac{12+6+4+3}{12})=500$$

=> $$k=500\times\frac{12}{25}=240$$

$$\therefore$$ Sum of gifts received by 1st kid and 2nd kid = $$a+b=k+\frac{k}{2}=3\frac{k}{2}$$

= $$3\times\frac{240}{2}=360$$

=> Ans - (A)