A train takes 67 seconds to cross a bridge of length 266 m. If the same train takes 29 seconds to cross a sign board, find the length of the train.

Let length of train = $$l$$ m and speed = $$s$$ m/s

Speed of train which takes 67 seconds to cross a bridge of length 266 m = $$s=\frac{266+l}{67}$$ -----------(i)

Also, $$s=\frac{l}{29}$$ --------------(ii)

Substituting value of $$s$$ from equation (ii) in (i), we get :

=> $$\frac{l}{29}=\frac{266+l}{67}$$

=> $$67l=(266\times29)+29l$$

=> $$67l-29l=38l=266\times29$$

=> $$l=\frac{266\times29}{38}=203$$

$$\therefore$$ Length of train = 203 m

=> Ans - (A)