RPF 13 Jan 2019

Marks obtained = 79 + 95 + 31 + 35 = 240

Maximum marks = 120 + 130 + 70 + 80 = 400

$$\therefore$$ Overall percentage obtained by him = $$\frac{240}{400}\times100=60\%$$

=> Ans - (B)

If total salary is 100%, then % salary remaining after the donations = $$100-(13+12+14+16)=45\%$$

According to ques, $$45\%\equiv Rs.$$ $$18,900$$

Thus, amount donated to organization for Visually challenged = $$13\%\equiv\frac{18900}{45}\times13$$

= $$420\times13=Rs.$$ $$5,460$$

=> Ans - (D)

% of non defective bulbs = $$100-19=81\%\equiv1944$$

=> Number of defective products = $$19\%\equiv\frac{1944}{81}\times19$$

= $$24\times19=456$$

=> Ans - (B)

Let number of employees in the firm initially = 100 and wages per head = Rs. 100

=> Total wages = $$100\times100=Rs.$$ $$10,000$$

Number of employees after decrease of 14% = $$100-\frac{14}{100}\times100=86$$

Similarly, new wages per head = $$Rs.$$ $$114$$

=> New wages = $$86\times114=Rs.$$ $$9804$$

$$\therefore$$ Decrease in total wages = $$\frac{10000-9804}{10000}\times100=1.96\%$$

=> Ans - (D)

Expression : $$132 - [ 5^2 - 4^2 + \sqrt{(144 \div 12 + 132(2 \times 2 \div 4))}]$$

= $$132 - [ 5^2 - 4^2 + \sqrt{(12 + 132(1))}]$$

= $$132 - [25-16 + \sqrt{144}]$$

= $$132-(9+12)=111$$

=> Ans - (B)

Given : $$x=0.7822222....$$

=> $$100x=78.22222.....$$ ------------(i)

=> $$1000x=782.2222.....$$ ------------(ii)

Subtracting equation (i) from (ii), we get :

=> $$900x=782.2222-78.2222=704$$

=> $$x=\frac{704}{900}$$

=> Ans - (A)

Let marked price = Rs. $$100x$$

After 1st discount of 10%, selling price = $$100x-(\frac{10}{100}\times100x)=Rs.$$ $$90x$$

Similarly, after 2nd discount of 20%, selling price = $$90x-(\frac{20}{100}\times90x)=Rs.$$ $$72x$$

According to ques, => $$72x=1764$$

=> $$x=\frac{1764}{72}=24.5$$

$$\therefore$$ Cost price = $$\frac{50}{100}\times100\times24.5=Rs.$$ $$1225$$

=> Ans - (A)

Average weight of 87 Notebooks in a box = 8.7 kg

=> Total weight = $$87\times8.7=756.9$$ kg

Let weight of new book = $$x$$ kg

=> New average = $$\frac{756.9+x}{88}=8.8$$

=> $$756.9+x=88\times8.8=774.4$$

=> $$x=774.4-756.9=17.5$$ kg

=> Ans - (C)

Speed of train = 54 kmph = $$54\times\frac{5}{18}=15$$ m/s

Let length of bridge = $$x$$ m

Using, speed = distance/time

=> $$15=\frac{135+x}{27}$$

=> $$135+x=27\times15=405$$

=> $$x=405-135=270$$ m

=> Ans - (A)

Principal sum = Rs. 7800

Rate of interest = 11% and time period = 5 years

Simple interest = $$\frac{P\times R\times T}{100}$$

= $$\frac{7800\times11\times5}{100}=Rs.$$ $$4290$$

Thus, total amount after 5 years = $$Rs.$$ $$(7800+4290)=Rs.$$ $$12,090$$

$$\therefore$$ Remaining amount after half of the total amount is been invested in Share market = $$\frac{12090}{2}=Rs.$$ $$6045$$

=> Ans - (B)