RPF 13 Jan 2019

Production of company Z in 2001 (in thousands) = 68

Production of company Y in 2002 (in thousands) = 71

=> Required difference = 71 - 68 = 3

=> Ans - (D)

Let usual speed = $$10$$ m/min and usual time taken = $$t$$ min

=> New speed = $$9$$ m/min and new time = $$(t+24)$$ min

Also, speed is inversely proportional to time.

=> $$\frac{10}{9}=\frac{t+24}{t}$$

=> $$10t=9t+216$$

=> $$10t-9t=t=216$$

$$\therefore$$ Usual time taken = 216 minutes

=> Ans - (D)

Let amount received by Ankit, Babu, Christo and David be $$5x,4x,3x$$ and $$2x$$ respectively.

According to ques, => $$3x-2x=114$$

=> $$x=114$$

$$\therefore$$ Babu's share = $$4\times114=Rs.$$ $$456$$

=> Ans - (A)

Production of paper (in thousands) by company X in 2002 = 66

Production of paper (in thousands) by company X in 2005 = 69

=> % increase in production = $$\frac{(69-66)}{66}\times100$$

= $$\frac{50}{11}\approx4.55\%$$

=> Ans - (C)

Numbers which are divisible by 24, must first be divisible by 3 and also by 8. Checking divisibility by 8.

146604 and 166044 are not divisible by 8, so of the middle two numbers, only second number is divisible by 3.

Thus, 166440 is divisible by 24.

=> Ans - (B)

Expression : $$((4^2)^3 \div 16^2 ) \times ([20 - 4] \div 4)$$

= $$(\frac{4^6}{4^4}) \times (\frac{16}{4})$$

= $$4^2\times4=64$$

=> Ans - (B)

Rate of interest = 6% and time period = 2 years

Let principal sum = Rs. $$P$$

Also, difference between compound interest and simple interest for 2 years = $$P(\frac{r}{100})^2$$

=> $$P(\frac{6}{100})^2=180$$

=> $$P=180\times\frac{10000}{36}$$

=> $$P=Rs.$$ $$50,000$$

=> Ans - (A)

The amount gets doubled in 7 years.

In case of compound interest, the amount will become $$2^n$$ times in $$7n$$ years

=> Final amount = $$64=(2)^6$$

Thus, after $$7\times6=42$$ years, amount will become 64 times.

=> Ans - (A)

Let number of 1 rupee, 5 rupees and 10 rupees respectively be $$3x,5x$$ and $$7x$$

Total amount = $$(1\times3x)+(5\times5x)+(10\times7x)=2352$$

=> $$3x+25x+70x=2352$$

=> $$x=\frac{2352}{98}=24$$

$$\therefore$$ Number of 10 rupees coins = $$7\times24=168$$

=> Ans - (D)

Sum of digits of 36367 = 3+6+3+6+7=25

Now, when 25 is divided by 9, => $$25=9\times2+7$$

Thus, remainder = 7

=> Ans - (D)