Question 106

Simplify:
$$((4^2)^3 \div 16^2 ) \times ([20 - 4] \div 4)$$

ExpressionΒ :Β $$((4^2)^3 \div 16^2 ) \times ([20 - 4] \div 4)$$

=Β $$(\frac{4^6}{4^4}) \times (\frac{16}{4})$$

= $$4^2\times4=64$$

=> Ans - (B)

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