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Simplify:$$((4^2)^3 \div 16^2 ) \times ([20 - 4] \div 4)$$
68
64
56
128
Expression : $$((4^2)^3 \div 16^2 ) \times ([20 - 4] \div 4)$$
= $$(\frac{4^6}{4^4}) \times (\frac{16}{4})$$
= $$4^2\times4=64$$
=> Ans - (B)
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