RPF 10 Jan 2019 Slot 1

Let the length and breadth of rectangle be 100 cm

=> Original area = $$100\times100=10000$$ $$cm^2$$

Increasing the length by 8%, => new length = $$100\times\frac{108}{100}=108$$ cm

Similarly, new breadth = $$98$$ cm

=> New area = $$108\times98=10584$$ $$cm^2$$

$$\therefore$$ Area is increased by = $$\frac{10584-10000}{10000}\times100=5.84\%$$

=> Ans - (D)

The amount gets tripled in 4 years.

In case of compound interest, the amount will become $$3^n$$ times in $$4n$$ years

=> Final amount = $$27=(3)^3$$

Thus, after $$4\times3=12$$ years, amount will become 27 times.

=> Ans - (A)

Since, there are an equal number of male and female employees in the company, and also the average productivity is 75 calls per day which is equal to the number of calls attended by the males.

Thus, number of calls attended per day by a female employee will also equal to = 72

=> Ans - (A)

Quantity of milk in 56 litres mixture = $$\frac{3}{(3+4)}\times56=24$$ litres

=> Quantity of water = $$56-24=32$$ litres

Let $$x$$ litres of water is to be added.

=> $$\frac{24}{32+x}=\frac{3}{5}$$

=> $$120=96+3x$$

=> $$3x=120-96=24$$

=> $$x=\frac{24}{3}=8$$

$$\therefore$$ Quantity of water to be further added is 8 litres.

=> Ans - (C)

Let usual speed = $$17$$ m/min and usual time taken = $$t$$ min

=> New speed = $$16$$ m/min and new time = $$(t+5)$$ min

Also, speed is inversely proportional to time.

=> $$\frac{17}{16}=\frac{t+5}{t}$$

=> $$17t=16t+80$$

=> $$17t-16t=t=80$$

$$\therefore$$ Usual time taken = 80 minutes

=> Ans - (C)

Let salary of Hamid, Celement and Ganesh be $$3x,5x$$ and $$7x$$ respectively.

According to ques, => $$7x-3x=860$$

=> $$x=\frac{860}{4}=215$$

$$\therefore$$ Celement's salary = $$5\times215=Rs.$$ $$1075$$

=> Ans - (A)

Expression : $$\sqrt{169} \div 13 + \sqrt{196} = 3\times x$$

= $$\frac{13}{13}+14=3x$$

=> $$x=\frac{15}{3}=5$$

=> Ans - (A)

Let cost price = Rs. 100

=> Marked price = $$100\times(\frac{142}{100})=Rs.$$ $$142$$

Thus, selling price after discount of 42% = $$142\times\frac{100-42}{100}=Rs.$$ $$82.36$$

$$\therefore$$ Loss % = $$\frac{100-82.36}{100}\times100=17.64\%$$

=> Ans - (A)

Average weight of 63 Notebooks in a box = 6.3 kg

=> Total weight = $$63\times6.3=396.9$$ kg

Let weight of new book = $$x$$ kg

=> New average = $$\frac{396.9+x}{64}=6.4$$

=> $$396.9+x=64\times6.4=409.6$$

=> $$x=409.6-396.9=12.7$$ kg

=> Ans - (B)