RPF 10 Jan 2019 Slot 1 Question 117
Question 117
Find the value of x.
$$\sqrt{169} \div 13 + \sqrt{196} = 3\times x$$
Solution
Expression :Â $$\sqrt{169} \div 13 + \sqrt{196} = 3\times x$$
= $$\frac{13}{13}+14=3x$$
=> $$x=\frac{15}{3}=5$$
=> Ans - (A)
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