Question 117

# Find the value of x.$$\sqrt{169} \div 13 + \sqrt{196} = 3\times x$$

Solution

Expression : $$\sqrt{169} \div 13 + \sqrt{196} = 3\times x$$

= $$\frac{13}{13}+14=3x$$

=> $$x=\frac{15}{3}=5$$

=> Ans - (A)