RPF 10 Jan 2019 Slot 1 Question 117

Question 117

Find the value of x.
$$\sqrt{169} \div 13 + \sqrt{196} = 3\times x$$

Solution

Expression : $$\sqrt{169} \div 13 + \sqrt{196} = 3\times x$$

= $$\frac{13}{13}+14=3x$$

=> $$x=\frac{15}{3}=5$$

=> Ans - (A)



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