In a mixture of 56 litres, the ratio of milk and water is 3:4. If this ratio is to be 3:5, then the quantity of water to be further added is (in Litres)
Quantity of milk in 56 litres mixture = $$\frac{3}{(3+4)}\times56=24$$ litres
=> Quantity of water = $$56-24=32$$ litres
Let $$x$$ litres of water is to be added.
=> $$\frac{24}{32+x}=\frac{3}{5}$$
=> $$120=96+3x$$
=> $$3x=120-96=24$$
=> $$x=\frac{24}{3}=8$$
$$\therefore$$ Quantity of water to be further added is 8 litres.
=> Ans - (C)
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