OICL Specialist Officer Finance Exam 2015 Question Paper

Let the total number of students in all colleges together = $$100x$$

=> Number of students in A = $$\frac{25}{100} \times 100x = 25x$$

Number of students in C = $$\frac{60}{100} \times 25x = 15x$$

Number of students in college D = $$\frac{3}{4} \times 15x = \frac{45x}{4}$$

Number of students in E = $$\frac{1}{2} \times 15x = 7.5x = 450$$

=> $$x = \frac{450}{7.5} = 60$$

Total students in colleges B & C = 2475 + 900 = 3375

Total students in colleges A & D = 1500 + 675 = 2175

=> Required % = $$\frac{3375 - 2175}{2175} \times 100$$

= $$55.17 \approx 55 \%$$

Let the total number of students in all colleges together = $$100x$$

=> Number of students in A = $$\frac{25}{100} \times 100x = 25x$$

Number of students in C = $$\frac{60}{100} \times 25x = 15x$$

Number of students in college D = $$\frac{3}{4} \times 15x = \frac{45x}{4}$$

Number of students in E = $$\frac{1}{2} \times 15x = 7.5x = 450$$

=> $$x = \frac{450}{7.5} = 60$$

Ratio of male and female students in college D = 13 : 12

=> Female students in college D = $$\frac{12}{25} \times 675 = 324$$

=> Male students in college D = $$675 - 324 = 351$$

In college E, number of females = $$\frac{3}{4} \times 324 = 243$$

=> Male students in college E = $$450 - 243 = 207$$

$$\therefore$$ Required ratio = $$\frac{207}{243} = 23 : 27$$

Let the total number of students in all colleges together = $$100x$$

=> Number of students in A = $$\frac{25}{100} \times 100x = 25x$$

Number of students in C = $$\frac{60}{100} \times 25x = 15x$$

Number of students in college D = $$\frac{3}{4} \times 15x = \frac{45x}{4}$$

Number of students in E = $$\frac{1}{2} \times 15x = 7.5x = 450$$

=> $$x = \frac{450}{7.5} = 60$$

Number of students in university PQR = $$\frac{28}{100} \times 6000 = 1680$$

Students studying in science or commerce stream in university PQR = $$\frac{60}{100} \times 1680 = 1008$$

Ratio between students of science and commerce stream = 7 : 5

=> Number of students studying in Science stream = $$\frac{7}{12} \times 1008 = 588$$

Let the total number of students in all colleges together = $$100x$$

=> Number of students in A = $$\frac{25}{100} \times 100x = 25x$$

Number of students in C = $$\frac{60}{100} \times 25x = 15x$$

Number of students in college D = $$\frac{3}{4} \times 15x = \frac{45x}{4}$$

Number of students in E = $$\frac{1}{2} \times 15x = 7.5x = 450$$

=> $$x = \frac{450}{7.5} = 60$$

Total number of students in B,C and E = 2475 + 900 + 450 = 3825

=> Required average = $$\frac{3825}{3} = 1275$$

Let the total number of students in all colleges together = $$100x$$

=> Number of students in A = $$\frac{25}{100} \times 100x = 25x$$

Number of students in C = $$\frac{60}{100} \times 25x = 15x$$

Number of students in college D = $$\frac{3}{4} \times 15x = \frac{45x}{4}$$

Number of students in E = $$\frac{1}{2} \times 15x = 7.5x = 450$$

=> $$x = \frac{450}{7.5} = 60$$

Number of teachers in college A = $$\frac{1}{20} \times 1500 = 75$$

=> Number of teacher in college C = $$75 - 15 = 60$$

In January 2013,

Total number of females who visited the park = $$\frac{7}{12} \times 120,000 = 70,000$$

=> Number of males = $$120,000 - 70,000 = 50,000$$

For visitors who were less than or equal to 20 years :

Number of visitors (both male and female) = $$\frac{65}{100} \times 120,000 = 78,000$$

Number of females = $$\frac{60}{100} \times 78,000 = 46,800$$

Number of males = $$78,000 - 46,800 = 31,200$$

For visitors above age group of 20 years :

Number of females = $$70,000 - 46,800 = 23,200$$

Number of males = $$50,000 - 31,200 = 18,800

$$\therefore$$ Required difference = $$23,200 - 18,800 = 4,400$$

Number of visitors in November 2012 (in '000) = 65

Number of visitors in all the given months together (in '000)

= 55 + 75 + 65 + 126 + 120 = 441

=> Required % = $$\frac{65}{441} \times 100$$

= $$17.739 \approx 14.74 \%$$

Female visitors (in '000) to the park in the month of October 2012 = $$\frac{2}{5} \times 75 = 30$$

Female visitors (in '000) to the park in the month of December 2012 = $$\frac{4}{7} \times 126 = 72$$

=> Required ratio = $$\frac{30}{72} = \frac{5}{12}$$

= 5 : 12

Total number of the male visitors in September 2012 = $$\frac{4}{11} \times 55,000 = 20,000$$

Total number of the male visitors in October 2012 = $$\frac{3}{5} \times 75,000 = 45,000$$

=> Sum = $$20,000 + 45,000 = 65,000$$

Total number of male visitors in November 2012 = $$\frac{5}{8} \times 65,000 = 40,625$$

Total number of male visitors in December 2012 = $$\frac{3}{7} \times 1,26,000 = 54,000$$

=> Sum = $$40,625 + 54,000 = 94,625$$

$$\therefore$$ Difference = $$94,625 - 65,000 = 29,625$$

Number of visitors who had visited the park of age group less than or equal to 20 years in the months of :

Sep : $$\frac{40}{100} \times 55,000$$ = 22,000

Oct : $$\frac{52}{100} \times 75,000$$ = 39,000

Nov : $$\frac{55}{100} \times 65,000$$ = 35,750

Dec : $$\frac{60}{100} \times 126,000$$ = 75,600

Jan : $$\frac{65}{100} \times 120,000$$ = 78,000

=> Total visitors = 22000 + 39000 + 35750 + 75600 + 78000 = 2,50,350

$$\therefore$$ Required average = $$\frac{250350}{5} = 50070$$