The number of visitors in November 2012 form what percent of total number of visitors in all the given months together? (round it off to two digits after decimal)

Solution

Number of visitors in November 2012 (in '000) = 65

Number of visitors in all the given months together (in '000)

= 55 + 75 + 65 + 126 + 120 = 441

=> Required % = $$\frac{65}{441} \times 100$$

= $$17.739 \approx 14.74 \%$$

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