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NPAT Common 2020 QP2

Instructions

For the following questions answer them individually

NPAT Common 2020 QP2 - Question 81


If $$U=\left\{X\mid x\epsilon N,x\leq 10\right\}$$ is the universal set, and $$A = \left\{1,3,5,7,9 \right\}, B = \left\{2,4,6,8,10 \right\} \text{and}  C = \left\{l,2,3,4 \right\}$$. The number of elements in $$\left[A-(B\cap C)\right]-(B^{'}\cap C^{'})$$, where B'and C' are the complements of Band C, respectively is:

NPAT Common 2020 QP2 - Question 82


A and Bare two sets such that $$n(A) = 12, n(B) = 15  \text{and}  n(A \cup B) = 20$$. Then, $$n(B \cap A') - n(A \cap B') =$$

NPAT Common 2020 QP2 - Question 83


Let A = { 1,2,5}, B = { 1,2,3,4} and C = {2,5,6} be the three sets. If $$D=\left[A\times(B\cap C)\right]\cap\left[(A-B)\times C\right]$$, then which of the following is true?

NPAT Common 2020 QP2 - Question 84


If $$f(x)=\frac{x-1}{x+1}$$, then for $$k > 0$$, $$f^{-1}\left(\frac{1}{2k}+3 \right)=$$

NPAT Common 2020 QP2 - Question 85


Which of the following functions satisfies these two criteria: $$f(0) = 0$$ and $$f(x+1) = 2f(x)+ 1$$ ?

NPAT Common 2020 QP2 - Question 86


If $$f(x)=\frac{1}{x^{2}+1}, 0 < x < 1$$, then $$f^{-1}\left(\frac{1}{4}\right) + f^{-1}\left(\frac{3}{4}\right)=$$

NPAT Common 2020 QP2 - Question 87


In an examination, 82% of students passed in Mathematics, 70% passed in Science and 13% failed in both the subjects. lf 299 students passed in both the subjects, then the total number of students who appeared in the examination is:

NPAT Common 2020 QP2 - Question 88


The value of $$(\frac{5}{13} \text{ }of\text{ } 1\frac{14}{25}+2\frac{3}{10}-\frac{7}{18}\text{ }of \text{ }1\frac{1}{35})\times(3\frac{1}{5}\div 4\frac{1}{5} \text{ }of \text{ }5\frac{1}{3})$$ hes between:

NPAT Common 2020 QP2 - Question 89


The income of A is $$\frac{3}{4}$$ of B's income, and the expenditure of A is $$\frac{4}{5}$$ of B's expenditure. If A:s income is $$\frac{9}{10}$$ of B's expenditure, then the ratio of savings of A and B is:

NPAT Common 2020 QP2 - Question 90


If $$\large \frac{46}{159}=\frac{1}{x+\frac{1}{y+\frac{1}{z+\frac{1}{4}}}}$$, where $$x, y  \text{and}  z$$ are positive integers, then the value of $$(2x + 3y - 4z)$$ is:

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