MAH MBA CET Previous Paper 2025 Slot-1

Neena told Deepali that the mother-in-law of Deepali is Neena's father's granddaughter's father's grandfather's daughter-in-law.

Neena's father's granddaughter means that there is a person who is the daughter of either Neena or her sibling. Father of the granddaughter means that he is the husband of either Neena or her sibling. 

Now, daughter-in-law of the Grandfather of the husband means the mother of the husband of Neena or her sibling i.e. mother-in-law. It means that the mother-in-law mentioned in the question is the mother-in-law of either Neena or her sibling. 

But, it is mentioned that the mother-in-law in this question is for Deepali. 

Hence, Deepali is the sister of Neena. 

Option A.   

In a dice, the sum of the numbers on the opposite sides is equal to 7 i.e. (1,6) ; (2,5) ; (3,4).

Now, Arnav got 3 when he rolled the dice. Hence, the opposite side of the face of the dice will be 4. 

Now, 4 is multiplied to itself for 4 times. 

$$\therefore\ \left(4\times4\times4\times4\right)=256$$

Hence, the answer is 256. 

Option C 

In the above series, 3 occurs 6 times. 

Out of those 6 times, 3 is preceded by a number which is a multiple of 2 (4,8,4). 

Out of the remaining 3 times, one 3 is followed by 1 which is not a prime number. Hence, we can rule that out. 

The only possible cases remaining are two where 3 is followed by a prime number and not preceded by a number which is multiple of 2 (The first digit which is followed by 5 and not preceded by any number and 7,2). 

Hence, we have 2 such 3. 

Option B. 

In the given series, 8 13 10 15 12, the difference between the numbers are in the form of 5, -3, 5, -3 etc in the alternate form. 

Difference between 8 and 13 = 5

Difference between 13 and 10 = -3

Difference between 10 and 15 = 5

Difference between 15 and 12 = -3

Hence, the difference between 12 and the next number must be 5. 

So, the required number is 17. 

Option E.

Roshesh and Urus are at the two extremes and their immediate neighbours are either Quila and Tanaav. 

It is given that, Pravesh is fourth to the right of Tanaav. It means that Tanaav can't be the neighbour of a person who is at the extreme right.

So, two cases can be formed. 

Case 1: Roshesh is at the immediate left and Urus is at the immediate right. 

Now, Quila and Tanaav will be their immediate neighbours of Urus and Roshesh respectively and Pravesh will be fourth to the right of Tannav. 

Required arrangement: (R, T, , , , P, Q, U) 

It is given that, Wahab is the immediate left of Pravesh and Wahab is second to the right of Smitha. 

Required arrangement: (R, T, S, , W, P, Q, U)

Now, only one place is left and it will be allotted to Vihaaz. 

Final arrangement: (R, T, S, V, W, P, Q, U)

Case 2: Roshesh is at the immediate right and Urus is at the immediate left. 

Now, Quila and Tanaav will be their immediate neighbours of Roshesh and Urus respectively and Pravesh will be fourth to the right of Tannav. 

Required arrangement: (U, T, , , , P, Q, R)

It is given that, Wahab is the immediate left of Pravesh and Wahab is second to the right of Smitha.

Required arrangement: (U, T, S, , W, P, Q, R)

Now, only one place is left and it will be allotted to Vihaaz.

Final arrangement: (U, T, S, V, W, P, Q, R)

Hence, Vihaaz and Pravesh are the immediate neighbours of Wahaab. 

Option B. 

From the 2nd condition, P is the father of Q and from the 1st condition, R is the mother of Q.

Hence, R is the wife of P.

Option D. 

UNR ICF LEI OGL RIO

In the above series, look at the changing pattern from ICF to RIO

From ICF to LEI, 

I + 3 = L

C + 2 = E

F + 3 = I

From LEI to OGL, 

L + 3 = O

E + 2 = G

I + 3 = L 

Similarly, from OGL to RIO, 

O + 3 = R

G + 2 = I 

L + 3 = O

Hence, we can see a clear pattern that the first and last term is increasing by 3 and the second term is increasing by 2. 

R + 3 = U

I + 2 = K 

O + 3 = R

Hence, the final term will be UKR. 

Option B. 

A stream is flowing from west to east and it takes a left turn in the middle. So, now the stream is facing North. 

Now, it comes across an island and covers a quarter circle of the island in the counter clockwise direction. 

The above diagram shows the way the stream is moving. 

Hence, after taking a right turn from the island, the stream is again facing East. 

Option A.

In option A, the name of the animal is Lion and we know that Dog is called Lion. Hence, the actual animal in the option A is a dog. 

In option B, the name of the animal is Bison and we know that Lion is called Bison. Hence, the actual animal in the option B is a Lion.

In option C, the name of the animal is Snake and we know that Bison is called Snake. Hence, the actual animal in the option C is a Bison.

In option D, we don't know the actual animal as the name Dog is not assigned to any of the animals in the question. 

In option E, the name of the animal is Mongoose and we know that Snake is called Mongoose. Hence, the actual animal in the option D is a Snake.

Hence, we can only pet a dog which is called Lion (given). 

Option A.

It is given that Dony is at the middle of the row. So, he can't be at the extreme of the arrangement. Hence, all the options which contains Dony can be eliminated (Option A, B and C). 

It is also given that Tony is adjacent to Dony. Which means that Tony can't be at the extremes as Dony is in the middle of the arrangement. 

Hence, we can also reject the condition is which it is given that Tony is at the extremes (Option D). 

So, the only option left is Option E. Which means that, Sony and Mony will be at the extremes.