JEE (Advanced) 2008 Paper-2
For the following questions answer them individually
Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H, gas at the cathode is (1 Faraday = 96500 C mol$$^{-1}$$)
Among the following, the surfactant that will form micelles in aqueous solution at the lowest molar concentration at ambient conditions is
Solubility product constants $$(K_{sp})$$ of salts of types $$MX, MX_2$$ and $$M_3X$$ at temperature ‘T’ are $$4.0 \times 10^{-8}, 3.2 \times 10^{-14}$$ and $$2.7 \times 10^{-15}$$, respectively. Solubilities (mol dm$$^{-3}$$) of the salts at temperature 'T' are in the order
STATEMENT-1: Aniline on reaction with $$NaNO_2/HCl$$ at $$0^\circ C$$ followed by coupling with $$\beta$$ - naphthol gives a dark blue coloured precipitate.
and
STATEMENT-2: The colour of the compound formed in the reaction of aniline with $$NaNO_2/HCl$$ at $$0^\circ C$$ followed by coupling with $$\beta$$ - naphthol is due to the extended conjugation.
STATEMENT-1: $$[Fe(H_2O)_5NO]SO_4$$ is paramagnetic.
and
STATEMENT-2: The Fe in $$[Fe(H_2O)_5NO]SO_4$$ has three unpaired electrons.
STATEMENT-1: The geometrical isomers of the complex $$[M(NH_3)_4Cl_2]$$ are optically inactive.
and
STATEMENT-2: Both geometrical isomers of the complex $$[M(NH_3)_4Cl_2]$$ possess axis of symmetry.
STATEMENT-1: There is a natural asymmetry between converting work to heat and converting heat to work.
and
STATEMENT-2: Noprocessis possible in which the sole result is the absorption of heat from a reservoir and its complete conversion into work.
A tertiary alcohol H upon acid catalysed dehydration gives a product I. Ozonolysis of I leads to compounds J and K. Compound J upon reaction with KOH gives benzyl alcohol and a compound L, whereas K on reaction with KOH gives only M.
