IIFT 2013 Question Paper

Let us start by making a table as shown below:-

We are given that, The professor in room number 203 published in 12 journals and donated to 8 institutions last year. Thus, put 12 and 8 in Row 3 and Row 4 of column 203.
The Mercury professor is staying in an odd numbered room. Thus, the Mercury professor is staying in either of room 201, 203 or 205.
The Mars professor is staying two rooms ahead of Pluto professor who is

staying two rooms ahead of the Mercury professor in ascending order of

room numbers. If the Mercury professor is staying in 203 or 205 then there will be no room for professor Mars.
Thus, the Mercury professor is staying 201, the Pluto professor is staying in 203 and the Mars professor is staying in 205.
Put these values in their respective columns.
The professor in room no. 202 has published in twice as many journals as the professor who donated to 8 institutions last year.
We know the Pluto donated to 8 institutes last year and has published in 12 journals.
Thus, the professor in room no. 202 has published 24 journals.
The table till now is:-

HenThe professor from Jupiter published in 8 journals less than the professor from Pluto but donated to 10 more institutions last year.
We know Pluto donated to 8 institutes last year and has published in 12 journals. Thus, the professor from Jupiter published in 4 journals and donated to 18 institutes.
The professors from Mercury and Jupiter do not stay in room number 206.
Thus, the professor from Jupiter has to stay in either 202 or 204.
But the professor in room no. 202 has published 24 journals which is not the case with the professor from Jupiter.
Thus, the professor from Jupiter has to stay in room 204.
The professor from Uranus and the Professor in room number 206 together published in a total of 40 journals.
From this we can say that the professor from Uranus is not staying in room 206 and thus is staying in room no 202.
Thus, the professor from Neptune is staying in room no. 206.
The professor from Uranus has published papers in 24 journals and thus, the professor from Neptune has published papers in 16 journals.
The professor who published in 16 journals donated to 24 institutions last year.
Thus, the professor from Neptune has donated to 24 institutes last year.
Thus, the final table is:-

Thus, the professor from the Jupiter University donated to 18 universities.
Hence, option C is the correct answer.

Let us start by making a table as shown below:-

HenThe professor from Jupiter published in 8 journals less than the professor from Pluto but donated to 10 more institutions last year.
We know Pluto donated to 8 institutes last year and has published in 12 journals. Thus, the professor from Jupiter published in 4 journals and donated to 18 institutes.
The professors from Mercury and Jupiter do not stay in room number 206.
Thus, the professor from Jupiter has to stay in either 202 or 204.
But the professor in room no. 202 has published 24 journals which is not the case with the professor from Jupiter.
Thus, the professor from Jupiter has to stay in room 204.
The professor from Uranus and the Professor in room number 206 together published in a total of 40 journals.
From this we can say that the professor from Uranus is not staying in room 206 and thus is staying in room no 202.
Thus, the professor from Neptune is staying in room no. 206.
The professor from Uranus has published papers in 24 journals and thus, the professor from Neptune has published papers in 16 journals.
The professor who published in 16 journals donated to 24 institutions last year.
Thus, the professor from Neptune has donated to 24 institutes last year.
Thus, the final table is:-

Let us start by making a table as shown below:-

 The professor from Jupiter published in 8 journals less than the professor from Pluto but donated to 10 more institutions last year.
We know Pluto donated to 8 institutes last year and has published in 12 journals. Thus, the professor from Jupiter published in 4 journals and donated to 18 institutes.
The professors from Mercury and Jupiter do not stay in room number 206.
Thus, the professor from Jupiter has to stay in either 202 or 204.
But the professor in room no. 202 has published 24 journals which is not the case with the professor from Jupiter.
Thus, the professor from Jupiter has to stay in room 204.
The professor from Uranus and the Professor in room number 206 together published in a total of 40 journals.
From this we can say that the professor from Uranus is not staying in room 206 and thus is staying in room no 202.
Thus, the professor from Neptune is staying in room no. 206.
The professor from Uranus has published papers in 24 journals and thus, the professor from Neptune has published papers in 16 journals.
The professor who published in 16 journals donated to 24 institutions last year.
Thus, the professor from Neptune has donated to 24 institutes last year.
Thus, the final table is:-

Let us start by making a table as shown below:-

We are given that, The professor in room number 203 published in 12 journals and donated to 8 institutions last year. Thus, put 12 and 8 in Row 3 and Row 4 of column 203.
The Mercury professor is staying in an odd numbered room. Thus, the Mercury professor is staying in either of room 201, 203 or 205.
The Mars professor is staying two rooms ahead of Pluto professor who is

staying two rooms ahead of the Mercury professor in ascending order of

room numbers. If the Mercury professor is staying in 203 or 205 then there will be no room for professor Mars.
Thus, the Mercury professor is staying 201, the Pluto professor is staying in 203 and the Mars professor is staying in 205.
Put these values in their respective columns.
The professor in room no. 202 has published in twice as many journals as the professor who donated to 8 institutions last year.
We know the Pluto donated to 8 institutes last year and has published in 12 journals.
Thus, the professor in room no. 202 has published 24 journals.
The table till now is:-

The professor from Jupiter published in 8 journals less than the

professor from Pluto but donated to 10 more institutions last year.
We know Pluto donated to 8 institutes last year and has published in 12 journals. Thus, the professor from Jupiter published in 4 journals and donated to 18 institutes.
The professors from Mercury and Jupiter do not stay in room number 206.
Thus, the professor from Jupiter has to stay in either 202 or 204.
But the professor in room no. 202 has published 24 journals which is not the case with the professor from Jupiter.
Thus, the professor from Jupiter has to stay in room 204.
The professor from Uranus and the Professor in room number 206 together published in a total of 40 journals.
From this we can say that the professor from Uranus is not staying in room 206 and thus is staying in room no 202.
Thus, the professor from Neptune is staying in room no. 206.
The professor from Uranus has published papers in 24 journals and thus, the professor from Neptune has published papers in 16 journals.
The professor who published in 16 journals donated to 24 institutions last year.
Thus, the professor from Neptune has donated to 24 institutes last year.
Thus, the final table is:-

Thus, among the given options the professor from Uranus published papers in the maximum number of journals.
(The actual answer to this question is cannot be determined as we do not know how many papers were published by the professor from Mercury)
Hence, option B is the correct answer.

Let us start by making a table as shown below:-

Thus, The professor from Jupiter published in 8 journals less than the professor from Pluto but donated to 10 more institutions last year.
We know Pluto donated to 8 institutes last year and has published in 12 journals. Thus, the professor from Jupiter published in 4 journals and donated to 18 institutes.
The professors from Mercury and Jupiter do not stay in room number 206.
Thus, the professor from Jupiter has to stay in either 202 or 204.
But the professor in room no. 202 has published 24 journals which is not the case with the professor from Jupiter.
Thus, the professor from Jupiter has to stay in room 204.
The professor from Uranus and the Professor in room number 206 together published in a total of 40 journals.
From this we can say that the professor from Uranus is not staying in room 206 and thus is staying in room no 202.
Thus, the professor from Neptune is staying in room no. 206.
The professor from Uranus has published papers in 24 journals and thus, the professor from Neptune has published papers in 16 journals.
The professor who published in 16 journals donated to 24 institutions last year.
Thus, the professor from Neptune has donated to 24 institutes last year.
Thus, the final table is:-

The given sequence is NFRSCA
We are given that If the first letter is a consonant and last letter is a vowel, both are to be coded as 0
In the given sequence N is a consonant and A is a vowel.
Thus, both N and A is to be coded 0. Code word fro F, R, S, C is 5, 3, % and 2 respectively
Thus, the required code word = 053%20
Hence, option D is the correct answer.

The given sequence is A R F T H E
We are given that:- If the first letter as well as the last letter are vowels, both are to be coded as the code of the last letter.
In the given sequence both A and E are vowels and thus, both are to be coded the code word of E(%)
The code word for R, F, T and H are 3, 5, 8 and # respectively.
Hence, the code word for the given sequence is %358#%
Hence, option A is the correct answer.

Let us draw the family tree for each option:-
A.

Thus, M is the uncle of T and thus, option A is not the right answer
B.

Thus, M is the uncle of T and thus, option B is the not the right answer.
C

Thus, there is no direct relation between T and M and thus, option C is not the correct answer.
Hence, none of these is the correct answer.
Hence, option D is the correct answer.

P is right of Q and T is left of R and right of P. Q is right of S
Thus, Q is to right of S, P is to the right of Q, T is to the right of P and R is to the right of T.
Thus, the arrangement is SQPTR.
Thus, P is in the middle.
Hence, option A is the correct answer.

It is given that Asatra Vriksh has a poisonous fruit. From this we can conclude that people should not eat the fruit of Asatra Vriksh.
There is no such information in the passage from which options A, B and D can be inferred.
Hence, option C is the correct answer.