$$ \ln \left( \frac{k_2}{k_1} \right) = \frac{E_a}{R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right) $$
where $$k_1$$ and $$k_2$$ are rate constants at temperatures $$T_1$$ and $$T_2$$.
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CAT Formulas
Chemical Kinetics
Activation Energy Calculation
$$ \ln \left( \frac{k_2}{k_1} \right) = \frac{E_a}{R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right) $$
where $$k_1$$ and $$k_2$$ are rate constants at temperatures $$T_1$$ and $$T_2$$.
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