Bayes' theorem

Rarely Tested

If $$B_1, B_2, \dots, B_n$$ partition sample space, then:
$$P(B_j|A) = \frac{P(B_j) \cdot P(A|B_j)}{\sum_{i=1}^{n} P(B_i) \cdot P(A|B_i)}$$

For any $$j = 1, 2, \dots, n$$.

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