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Match List I with List II :
Choose the correct answer from the options given below :
Discount is always calculated on the marked price or the regular price.
A: Regular price = 65, Sale price = 55
Discount = 10
Discount % = $$\dfrac{10}{65}=15.38\%$$
B: Regular price = 60, Sale price = 50
Discount = 10
Discount % = $$\dfrac{10}{60}=16.66\%$$
C: Regular price = 70, Sale price = 50
Discount = 20
Discount % = $$\dfrac{20}{70}=28.57\%$$
(Note: The correct discount percentage should be 28.57%, however, in actual exam, the correct option given was 14.29%)
D: Regular price = 75, Sale price = 65
Discount = 10
Discount % = $$\dfrac{10}{75}=13.33\%$$
Given below are two statements:
Statement I : The difference between the cost price and sale price of an article is ₹ 240. If the profit is 20%, then the selling price is ₹ 1440.
Statement II: If the cost price of 10 DVDs is equal to the selling price of 7 DVDs, then the gain percent is $$42\frac{6}{7}%$$
In the light of the above statements, choose the most appropriate answer from the options given below:
Statement I:
It is given, profit percentage = 20%
This implies, $$SP=\frac{120}{100}CP$$
It is given, $$\frac{120}{100}CP-CP=240$$
$$\frac{20}{100}CP=240$$
$$CP=1200$$
SP = 1200+240 = Rs 1440
Therefore, statement I is correct.
Statement II:
It is given,
10CP = 7SP
Profit % = $$\ \frac{\ SP-CP}{CP}\times100=\frac{300}{7}=42\frac{6}{7}\%$$
Therefore, statement II is correct.
The answer is option A.
If the selling price of 320 Web Cameras is equal to the cost price of 400 Web Cameras, then the percentage profit is :
It is given,
320SP = 400CP
4SP = 5CP
Profit percentage = $$\ \frac{\ SP-CP}{CP}\times100=\ \frac{\ \frac{5CP}{4}-CP}{CP}\times100=25\%$$
The answer is option D.
Four sheep farmers rented a pasture, Anil grazed his 24 sheep for 3 months, Bimal 10 sheep for 5 months, Champak 35 sheep for 4 months and Damodar 21 sheep for 3 months,. If Anil’s share of rent is Rs. 720, find the total rent of the pasture :
A : B : C : D = 24($$\frac{3}{12}$$) : 10($$\frac{5}{12}$$) : 35($$\frac{4}{12}$$) : 21($$\frac{3}{12}$$)
A : B : C ; D = 6 : $$\frac{25}{6}$$ : $$\frac{35}{3}$$ : $$\frac{21}{4}$$
A : B: C : D = 72 : 50 : 140 : 63
Anil's rent = $$\frac{72}{72+50+140+63}\times\ $$ Total rent
720 = $$\frac{72}{325}\times\ $$ T
T = Rs 3,250
Answer is option B.
If the cost price is 80% of the selling price, then what is the profit in percentage?
Given, cost price is 80% of selling price
C.P = 0.8 S.P
Profit = $$\ \frac{\ S.P\ -\ C.P}{C.P}\times\ 100$$
= $$\ \frac{\ S.P\ -\ 0.8S.P}{0.8S.P}\times\ 100$$
=$$\ \frac{0.2}{0.8}\times\ 100$$
= 25%
Answer is option B
A started a business with Rs. 50000. After three months, B joins with an investment of Rs. 60000 and A withdraws Rs. 10000 out of his capital. Three months later, B brought in Rs. 20000 more. At the end of the year, what should be the ratio in which they A and B share the profits?
Profit share = Investment * Time period
Now we get ratio of profit of A and B :
$$\frac{50,000\times\ 3\ +\ 40,000\times\ 9}{60,000\times\ 3\ +\ 80,000\times\ 6}$$
we get ratio as $$\frac{510}{660\ }=\ \frac{17}{22}$$
Mohan bought a trouser at 10% discount and sold it to Sohan at a loss of 10%. If Sohan paid Rs. 729 for the trouser to Mohan, then what was the undiscounted price of the trouser?
It is given that Mohan bought a trouser at 10% discount and sold it to Sohan at a loss of 10%
Now Sohan paid Rs 729
So S.P for Mohan = 729
This is sold at 10% loss
so cost price of Mohan = 729/0.9 =810
Now Mohan bought for 810 at 10% discount
so original price (1-0.1) =810
We get undiscounted price = 900
A shopkeeper claims to sell rice at cost price. He uses a false weight with the intention of selling rice at 25% profit. After selling Rice to a customer, he realizes that the customer has paid 10% less than what he should have paid. What is the actual profit percentage made by the shopkeeper?
Let cost price be 1000 per Kg of rice
Now to make 25% profit at 1000
He will sell 800 gm of rice
Now C.P of 800 gm of rice = 800
Now he sold at 10% less than 1000 so S.P = 900
Now therefore profit = $$\frac{900-800}{800}\times\ 100\ =\ \frac{100}{8}=12.5\ \%$$
In the year 2020, Production of Sugar (in Million Tonnes) by six major production units A-F of India are shown in the table given below:
What was approximate percentage decrease in sugar production of unit B in June as compared to April?
Production of unit B in April = 180
Production of unit B in June = 160
Now therefore percentage decrease = $$\frac{\left(180-160\right)}{180}\times\ 100\ \approx\ \ 11\%$$
Two successive discounts of 8% and 12% are equal to a single discount of:
Two successive discounts of $$x$$ and $$y$$ $$\equiv x+y-\frac{xy}{100}$$
= $$12+8-\frac{12\times8}{100}$$
= $$20-0.96=19.04\%$$
=> Ans - (B)
A shopkeeper marks his books at 25% above the cost price. Due to slump in the market, his cost reduces by 5%. And then,to boost his sale, he offered a discount of 8% due to which sales goes up by 25%. Compute the change in the shopkeepers profit.
Let cost price of each article = Rs. 100 and number of articles sold be $$x$$
=> Original selling price price = Rs. 125
=> Original profit = Rs. $$(125-100)x = Rs.$$ $$25x$$
After offering discount of 8%, => New selling price = $$\frac{92}{100}\times125=Rs.$$ $$115$$
Also, new cost price = $$\frac{95}{100}\times100=Rs.$$ $$95$$
$$\because$$ Sale increases by 25%, => Number of articles now sold = $$1.25x$$
=> New profit = Rs. $$(115-95)\times1.25x = Rs.$$ $$25x$$
$$\therefore$$ There is no change in profit.
=> Ans - (A)
By selling mangoes at the rate of 64 for Rs. 2,000, the vendor loses 40%. How many should he sell for Rs.1000 so as to gain 20%?
If 64 mangoes are sold at Rs.2000, each mango will be sold at Rs. $$\frac{2000}{64}$$
Hence Selling price (S.P) of each mango = Rs. 31.25
Given loss percentage of vendor at this S.P = 40%
Loss percentage = $$\frac{C.P - S.P}{C.P}\times 100$$
$$\Rightarrow \frac{40}{100} = \frac{C.P - S.P}{C.P}$$
$$\Rightarrow S.P = 0.6\times C.P$$
$$\Rightarrow C.P = \frac{31.25}{0.6} = 52$$
Therefore Cost Price of 1 mango (C.P) = Rs. 52
Let us calculate the S.P of each mango in order to get a 20% gain.
Gain percentage = $$\frac{S.P - C.P}{C.P}\times 100$$
$$\Rightarrow \frac{20}{100} = \frac{S.P - C.P}{C.P}$$
$$\Rightarrow S.P = 1.2\times C.P$$
$$\Rightarrow S.P = 62.5$$
So, to get a gain of 20% we need to sell each mango at Rs. 62.5
Let say we sold 'x' number of mangoes.
Selling price of these 'x' number of mangoes (S.P) = Rs. 62.5x
But given that this S.P = Rs. 1000
$$\Rightarrow 62.5x = 1000$$
$$\Rightarrow x = \frac{1000}{62.5} = 16$$.
Therefore a total of 16 mangoes are to be sold for Rs. 1000 to get a gain of 20%.
Two balls were bought for Rs. 37.40 at a discount of 15%. What must be the marked price of each of the ball?
Let the marked price of two balls be X
Given that they were bought at 37.40 rupees at 15% discount.
=> X x $$\ \frac{\ 85}{100}$$=37.40
X= 44
we have considered that the marked price of two balls is X i.e: 44 rupees.
The question is asking to find marked price of each ball
so, answer is 22 rupees
option B
A shopkeeper sells rice at the cost price, but uses false weight. He gains 20% in this process. What weight does he uses for one kilogram?
Let say cost price(C.P) of 1 kg(1000 g) of rice be Rs. 100
Given Shopkeeper is selling rice at cost price,
$$\Rightarrow$$ Selling price(S.P) = C.P = Rs. 100
If he had used correct weight of 1000 g then C.P would have also been Rs. 100.
But given that he uses false weight. Let the weight he had used be 'x' g.
For 1000 g of rice the C.P = Rs. 100
$$\Rightarrow$$ For '1' g of rice the C.P will be Rs. $$\frac{1}{10}$$
$$\Rightarrow$$ For 'x' g of rice the C.P will be Rs. $$\frac{x}{10}$$
Given that, by using this false weight the shop keeper gains 20%.
Gain percentage = $$\frac{S.P - C.P}{C.P}\times 100$$
$$\Rightarrow \frac{20}{100} = \frac{S.P - C.P}{C.P}$$
$$\Rightarrow S.P = 1.2\times C.P$$
$$\Rightarrow 100 = 1.2\times \frac{x}{10}$$
$$\Rightarrow x = 833.33$$
Hence the false weight used is 833.33 g
An electric appliance is priced at Rs. 600 initially. Because of market recession, price was successively reduced three times, each time by 10% of the price after the earlier reduction. What is the current price?
Initial price is given as 'I' = Rs. 600
After the first reduction, the initial price is reduced by 10%
$$\Rightarrow$$ the new price I' = $$600[1 - \frac{10}{100}] = 540$$
After second reduction, I' is reduced by 10%
$$\Rightarrow$$ the new price I'' = $$540[1 - \frac{10}{100}] = 486$$
After third reduction, I'' is reduced by 10%
$$\Rightarrow$$ the new price I''' = $$486[1 - \frac{10}{100}] = 437.4$$
Hence the Current price after three successive reductions is Rs. 437.4
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