AP Police SI Mains 2019 Arithmetic and Reasoning

Let say ,x is the equal installment to be paid.

So,

$$7620(1+1/6)^3= x(1+1/6)^2$$

+x(1+1/6)+x.

or,$$x=3430(approx).$$

So,A is correct choice.

Let say, 3 years back height of the tree was p.

So,$$p×(1.1)^3=1815.$$

or,$$p=1363.66$$

or approximately 1364 cms.

So, B is correct choice.

Let say ,total profit earned is k.

So,they will divide 0.60k equally among them ; each will get 0.30k.

And rest of the profit, i.e.0.40k will divide in the ratio of$$125000:85000=25:17.$$

So,one will get $$0.40k×(25/42)$$ and other one will get$$0.40k×(17/42)$$.

So,$$0.40k(25/42-17/42)=300.$$

or,$$(8/42)k=750.$$

or,$$k=3937.50$$

So, D is correct choice.

Let say capital invested by A and B are 5k and 6k respectively.

So,profit ratio would be

$$=5k×8:6k×12$$

$$=5:9.$$

So, B's amount remained in the business for 12 months.

D is correct choice.

Let say,total capital is C and total time is T.

A invested$$=C/3.$$ for T/3 period of time.

B invested$$=C/2.$$ for T/2 period of time.

C invested$$=C-C/2-C/3=C/6.$$ for T period of time.

Their profit ratio should be as follows: 

$$(C/3)(T/3):(C/2)(T/2):(C/6)T$$

$$=(1/9):(1/4):(1/6)$$

$$=4:9:6.$$

So, C is correct choice.

A,B,C will take the profit in following ratio

$$=6500×6:8400×5:10000×3$$

$$=39000:42000:30000$$

$$=39:42:30$$

$$=13:14:10.$$

Total profit$$=7400.$$

5% of 7400$$=370.$$

rest of profit$$=7400-370=7030.$$

A will get$$=7030×(13/37)=2470.$$ of rest of the profit.

So,Total profit part of A$$=2470+370.$$

$$=2840.$$

So,C is correct choice.

Let say Amount is P.

Compound interest

$$=P(1+r/n)^nt -P $$

and

Simple interest

$$=Pnr.$$

So,CI$$=P(1+0.10/2)^4-P=0.21550625P$$.

And SI$$=P×2×0.10=0.2P$$.

So,$$0.21550625P-0.2P=124.05$$

or,$$P=8000.$$

So,A is correct choice.

Let say,$$Amount=P$$ and 

$$rate of interest=r percent$$

So, according to the question,

$$P(1+r/100)^5=2×P$$.

$$or,(1+r/100)^5=2$$

So,$$r=14.86 percent$$

let say ,in x years it will become 8 times.

So,

$$P(1+r/100)^x=8P$$

or,$$(1+r/100)^x=2^(15/5)$$

or,$$(1+r/100)^x=(1+r/100)^15$$

So, x=15.

D is correct choice.

Let say he invested in scheme P,Q and R is p,q,r respectively.

So,$$r=1.5p  and  r=2.4q$$

so,$$1.5p=2.4q$$

or,$$p/q=24/15=8/5$$

Let say, $$p=8k  and  q=5k$$

So,$$r=12k.$$

So,

$$(8k×0.10+5k×0.12+12k×0.15)=3200$$

$$or,(0.8k+0.6k+1.8k)=3200.$$

or,$$3.2k=3200$$

or,$$k=1000.$$

So,amount invested in scheme Q was 

$$=5×1000=5000.$$

B is correct choice.

Simple interest from 10% interest rate for 5 years is$$=a×0.10×5=0.50a.$$(a is the principal amount).

Simple interest from 9% interest rate for 6 years is$$=b×0.09×6=0.54b.$$(b is the amount invested in this case)

According to the question,

$$0.50a=0.54b$$

or,$$a/b=54/50=27/25.$$

So, C is correct choice.