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can you once explain me the solution given for question 4 in probability topic test 1 dated 04.02.16

How to do long problems

Kulbushan takes every 3rd number counting from 1001 up to 4000 (1003, 1006, 1009, … , 3997, 4000) and writes them down in sequence. What will be the 251st digit (from the left) in this sequence?

what is mba

find the value of I133-9I + [5-211] + I8-9I / I110-9I +[19-101] +8

if x # y = 2(x+y/x-y), then find the value of (4#3)/7

find the value of the expression 1+4 division 3*9 of (6-2)

how to solve this find the value of 72540/5 +72540/25 +72540/125

akhilesh sing sir is the ans of the question 7 to the power 13+6 to the power 12+ 1 to the power 11+4 to the power 7 to the power 13 713 is odd if we add 6 to it, it will still be odd. it if we add 6 with 7 am i right sir odd12 and odd 12 means 13 to the power 12 sir odd12 is odd, if we add 1 to it it will become even.and 1 with 13 it becomes 14 the even number Now (even)11(even)11 will be even it mens sir 14 to the power11 and adding 4 to it will give even only. and adding 4 with14 it becomes 18 sir (Even)7(Even)7 is even so the final result is even. and 18 to the power 7 is even and so the ans is even sir am i right

I have been solving at least one rc everyday from cracku, but my accuracy and score does not seem to increase. Please suggest what else should I do?