Question 99

Given $$P(x,y) = x^2+ xy + y^2; Q(x,y) = x^2- xy + y^2.$$ Find the value of $$P(7, Q(9,4))$$

Name: Given P(x,y) = x^2+ xy + y^2; Q(x,y) = x^2- xy + y^2. Find the value of P(7, Q(9,4))
Uploaded: Feb. 1, 2021, 9:43 a.m.
Duration: 1 min 15 s
Description: Given P(x,y) = x^2+ xy + y^2; Q(x,y) = x^2- xy + y^2. Find the value of P(7, Q(9,4))

Solution

Q(x,y) = x^2- xy + y^2.$$

Q(9,4) = $$9^2-4\cdot9+4^2=81+16-36=61$$

P(7,61) = $$7^2+7\cdot61+61^2=\ 49+427+3721=4197$$

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IIFT 2018 Question Paper

Given $$P(x,y) = x^2+ xy + y^2; Q(x,y) = x^2- xy + y^2.$$ Find the value of $$P(7, Q(9,4))$$

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